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Russell Wilson signs extension in Seattle that makes him highest-paid NFL player


Russell Wilson won’t become a Giant. Instead, he has a giant contract extension in Seattle that makes him the NFL’s new highest-paid player.

Wilson, 30, and the Seahawks struck an 11th-hour deal at midnight Pacific time, just prior to Wilson’s self-imposed deadline for a long-term deal.

Wilson announced it himself on Twitter from bed.

“Hey, Seattle,” Wilson said, next to smiling wife Ciara. “We got a deal.”

Seattle Seahawks quarterback Russell Wilson (3) scrambles out of the pocket during an NFC wild-card NFL football game against the Dallas Cowboys in Arlington, Texas, Saturday, Jan. 5, 2019.(AP Photo/Roger Steinman) (Roger Steinman/AP)

The four-year, $140 million extension contains $65 million guaranteed at signing, $107 million total guaranteed, and a no-trade clause, per NFL Network. The $35 million annual average leapfrogs Green Bay’s Aaron Rodgers ($33.5 million average) for highest in the league.

The contract keeps Wilson under contract in Seattle for at least five more years, through the 2023 season, when Wilson will be 35.

The total value of those five years, which include the final year of his previous deal, is $157 million -- or $31.4 million per year.

Wilson was rumored to desire New York. There were reports he wished to leave Seattle.

Ciara is a model and entertainer, and FOX had reported New York was appealing for both Wilson and his wife.

Wilson re-committed to Seattle, though, and the no-trade clause gives him full control of his destiny.

NBC had reported that Wilson wanted to get creative with this contract, tying his deal’s terms to future increases in the salary cap with an eye on skyrocketing earnings connected to gambling revenue.

The Seahawks didn’t set a new precedent there, but Wilson got the no-trade clause, stayed in the Pacific Northwest, and the Giants are left with Eli Manning and whomever they decide to draft on April 25.